2x^2-20x=48

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Solution for 2x^2-20x=48 equation:


Simplifying
2x2 + -20x = 48

Reorder the terms:
-20x + 2x2 = 48

Solving
-20x + 2x2 = 48

Solving for variable 'x'.

Reorder the terms:
-48 + -20x + 2x2 = 48 + -48

Combine like terms: 48 + -48 = 0
-48 + -20x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-24 + -10x + x2) = 0

Factor a trinomial.
2((-2 + -1x)(12 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-2 + -1x)' equal to zero and attempt to solve: Simplifying -2 + -1x = 0 Solving -2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1x = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1x = 0 + 2 -1x = 0 + 2 Combine like terms: 0 + 2 = 2 -1x = 2 Divide each side by '-1'. x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(12 + -1x)' equal to zero and attempt to solve: Simplifying 12 + -1x = 0 Solving 12 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1x = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1x = 0 + -12 -1x = 0 + -12 Combine like terms: 0 + -12 = -12 -1x = -12 Divide each side by '-1'. x = 12 Simplifying x = 12

Solution

x = {-2, 12}

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